Robotics sum-2
Problem the input "R","L","U","D" denotes to right, left, up and down respectively. The integer that nearer to the above charecters are the points that move towards the graph.
Input: n="R10L5U5D10"
- If the input consists of R10 we should move 10 points towards right.
- If the input consists of L5 we should move 5 points towards left.
- If the input consists of U5 we should move 5 points towards up.
- If the input consists of D10 we should move 10 points towards down.
output
- After performing all the process print the X and Y coordinates.
Example-1:
Input : n = "R10L5U5D10" Output : 5 -5 Explain : The final output is x=5 and y=-5.
Example-2:
Input : n = "R7R3L4L2U12" Output : 4 12 Explain : The final output is x=4 and y=12.
Example-3:
Input : n = "U10L20R10" Output : -10 10 Explain : The final output is x=-10 and y=10.
Solution
public class Main
{
public static void main(String[] args)
{
String s = "R10L5U5D10";
char before = s.charAt(0);
int num = 0;
int x = 0,y = 0;
for (int i=0;i<s.length();i++)
{
if(s.charAt(i)>='0' && s.charAt(i)<='9')
{
num = (num*10) + Character.getNumericValue(s.charAt(i));
}
if(!(s.charAt(i) >= '0' && s.charAt(i) <= '9')||i == s.length()-1)
{
if(before=='R') x = x + num;
else if(before=='L') x = x-num;
else if(before=='D') y = y-num;
else
{
y = y + num;
}
num = 0;
before=s.charAt(i);
}
}
System.out.print(x+" "+y);
}
}
import re
n = "R10L5U5D10"
x1 = []
x2 = []
y1 = []
y2 = []
r = re.findall("R+[0-9]+",n)
l = re.findall("L+[0-9]+",n)
u = re.findall("U+[0-9]+",n)
d = re.findall("D+[0-9]+",n)
for i1 in range(len(r)):
k1 = r[i1]
a1 = int(k1[1:])
x1.append(a1)
for i2 in range(len(l)):
k2 = l[i2]
a2 = int(k2[1:])
x2.append(a2)
for i3 in range(len(u)):
k3 = u[i3]
a3 = int(k3[1:])
y1.append(a3)
for i4 in range(len(d)):
k4 = d[i4]
a4 = int(k4[1:])
y2.append(a4)
x = sum(x1)-sum(x2)
y = sum(y1)-sum(y2)
print(x,y)
Output
5 -5