Reverse bits

Problem to find the 8 bit binary value and return the decimal of that reversed binary value.

if n=2-->

binary value   = "10"
convert 8 bit  = "00000010"
reverse binary = "01000000"

decimal value of reverse binary value = 64.

Example-1:

Input    : n = 2
Output   : 64

Example-2:

Input    : n = 3
Output   : 192

Solution

n = 2

n = bin(n)

n = n[2:]

n = n[::-1]

a = 8-len(n)

b = n + ("0"*a)

b = b[::-1]

d = 0

for i in range(0,len(b)):

    if(b[i] == "1"):

        d += 2**i

print(d)

Output