Print times of character

Problem to print the times of characters.

Example-1:

Input    : n = "a3b2c1"
Output   : aaabbc

Example-2:

Input    : n = "a2b1c10"
Output   : aabcccccccccc

Solution

import re

n = "a3b2c1"

a = re.findall(r'[0-9]+',n)

b = [x for x in n if(x.isalpha())]

b = "".join(b)

d = ""

for i in range(len(a)):

    d += b[i] * int(a[i])

print(d)

Output

aaabbc