Neon number
Problem to find the neon number or not.
Neon number is the sum of digit in square value is Equal to the given value.
Example-1:
Input : n = 9 Output : Neon number Explain : 9*9 => 81 => 8+1 =>9
Example-2:
Input : n = 8 Output : Not a neon number Explain : 8*8 => 64 => 6+4 => 10
Solution
public class Main
{
public static void main(String [] args)
{
int n = 9;
int square = n*n;
int sum = 0;
while(square!=0)
{
sum = sum + square % 10;
square = square/10;
}
if(sum==n)
{
System.out.print("Neon number");
}
else
{
System.out.print("Not a neon number");
}
}
}
n = 9
sum = 0
x = str(n*n)
for i in x:
sum += int(i)
if(sum==n):
print("Neon number")
else:
print("Not a neon number")
Output
Neon number