Find the number is balanced or not

Problem to find the number balanced or not. The number length is always odd. Split the number into LHS and RHS in equal length.

if n = 1204003

          120   4   003
           ↓         ↓ 
          LHS       RHS

The sum of the LHS = The sum of the RHS.
So It's Balanced.

Example-1:

Input    : n = 1204003
Output   : Balanced 

Example-2:

Input    : n = 13522
Output   : Balanced 

Example-3:

Input    : n = 15723
Output   : Not Balanced  

Solution

n = 1204003

n = str(n)

a = len(n)//2

b = n[:a]

c = n[a+1:]

l = []

k = []

for x in b:

    l.append(int(x))

for y in c:

    k.append(int(y))

if(sum(l) == sum(k)):

    print("Balanced")

else:

    print("Not Balanced")

Output

Balanced