Find the count of continuous 0's and 1's number

Problem to count the continuous 0's and 1's numbers in given binary string.

Example-1:

Input    : n = "11000010001"
Output   : [2, 4, 1, 3, 1]

Example-2:

Input    : n = "10001"
Output   : [1, 3, 1]

Solution

n = "11000010001"

n = n + " "

k = 1

l = []

for i in range(1,len(n)):

    if(n[i-1] == n[i]):

        k += 1

        continue

    else:

        l.append(k)

        k = 1

print(l)

Output

[2, 4, 1, 3, 1]