# Find the (0 to 9) number in the given string of the possibilities

Problem to find number in words in the given string. And print the output in sorted order of found number.

## Example-1:

```Input    : s = "fighteuro"
Output   : 48
Explain  : The string has a "eight" and "four" in number words.It's sorted order is
48.
```

## Example-2:

```Input    : s = "ffoiuver"
Output   : 45
Explain  : The string has a "four" and "five" in number words.It's sorted order is
45.
```

# Solution

```
```
```from itertools import permutations

s = "fighteuro"

l = [ "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]

l1 = [ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

u = []

d1 = ""

n = ""

for i in range(3,6):

d = list(permutations(s,i))

k = ["".join(x) for x in d]

for y in range(len(l)):

if(l[y] in k):

d1 += l[y]

u.append(l[y])

if(sorted(d1) == sorted(s)):

for i in range(len(u)):

a = l.index(u[i])

n += str(l1[a])

n = sorted(n)

n = "".join(n)

print(n)

else:

print("No")
```

```48
```