Find the (0 to 9) number in the given string of the possibilities
Problem to find number in words in the given string. And print the output in sorted order of found number.
Example-1:
Input : s = "fighteuro" Output : 48 Explain : The string has a "eight" and "four" in number words.It's sorted order is 48.
Example-2:
Input : s = "ffoiuver" Output : 45 Explain : The string has a "four" and "five" in number words.It's sorted order is 45.
Solution
from itertools import permutations
s = "fighteuro"
l = [ "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
l1 = [ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
u = []
d1 = ""
n = ""
for i in range(3,6):
d = list(permutations(s,i))
k = ["".join(x) for x in d]
for y in range(len(l)):
if(l[y] in k):
d1 += l[y]
u.append(l[y])
if(sorted(d1) == sorted(s)):
for i in range(len(u)):
a = l.index(u[i])
n += str(l1[a])
n = sorted(n)
n = "".join(n)
print(n)
else:
print("No")
Output
48