Count unsorted columns

Problem to count the unsorted columns in given three string.

Example-1:

Input    : s1 = "hello"
           s2 = "world"
           s3 = "crazy"
Output   : 3
Explain  : unsorted columns are: h l o
                                 w r d
                                 c a y
           The three unsorted columns are (h,w,c),(l,r,a) and (o,d,y).

Example-2:

Input    : s1 = "live"
           s2 = "like"
           s3 = "love"
Output   : 3
Explain  : unsorted columns are: v
                                 k
                                 v
           The only one unsorted column is (v,k,v).

Solution

s1 = "hello"

s2 = "world"

s3 = "crazy"

k = 0

for i in range(len(s1)):

    a = s1[i] + s2[i] + s3[i]

    b = s1[i] + s2[i] + s3[i]

    c = sorted(b)

    d = "".join(c)

    if(a!=d):

        k += 1

print(k)

Output