Count the continuous character in an string

Problem to count the continuous character in an string.

Example-1:

Input    : s = "aabbccca"
Output   : "a2b2c3a1"

Example-2:

Input    : s = "xyzz"
Output   : "x1y1z2"

Solution

n = "aabbccca"

d = ""

count = 1

n = n + " "

for i in range(1,len(n)):

    if(n[i-1] == n[i]):

        count += 1

    else:

        d += n[i-1]

        d += str(count)

        count = 1

print(d)

Output

a2b2c3a1