Armstrong number
if given number equal to the power of each and every digit with length of the given number and sum the powered value.That is called Armstrong number.
Example-1:
Input : n=153 Output : Armstrong number Explain : 13+53+33=153. The output value is equal to the input value.
Example-2:
Input : n=1634 Output : Armstrong number Explain : 14+64+34+44=1634. The output value is equal to the input value.
Example-2:
Input : n=52 Output : Not a Armstrong number Explain : 52+22=29. The output value is not equal to the input value.
Solution
public class Main
{
public static void main(String [] args)
{
int n = 153;
int temp = n, sum = 0;
String s = "" + n;
int len = s.length();
while(temp != 0){
sum = sum + (int)Math.pow(temp % 10,len);
temp = temp/10;
}
if(n == sum){
System.out.print("Armstrong number");
}
else{
System.out.print("Not a Armstrong number");
}
}
}
n = 153
n = str(n)
k = 0
for i in range(len(n)):
k += (int(n[i]))**3
if(int(n) == k):
print("Armstrong number")
else:
print("Not a Armstrong number")
Output
Armstrong number